I use this code to make ajax call to change the content of div in main page without reloading the page :
function ajaxcall()
{
$.ajax({
type: "POST",
url: "/create.php",
success: function( returnedData ) {
$( '#container' ).html( returnedData );
}
}); }
and I call it like that :
<p><a onclick="ajaxcall()" >Create</a></p>
The issue is very complicated because I have to call 4 pages in the same div :
create.hmtl ; update.html; delete.html ; read.html
Also I have 2 different forms in the same page that required the same thing, I mean I should do the same thing for the second form with another div "container-1",then I have 2 div for exmaple in create.html :
create.html :
<div id="container">
....
</div>
<div id="container-1">
....
</div>
So I call create.html everytime but different div for different form, the question is to use a minimum clean code to do all what I explained above?
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